3x+6x^2=16

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Solution for 3x+6x^2=16 equation:



3x+6x^2=16
We move all terms to the left:
3x+6x^2-(16)=0
a = 6; b = 3; c = -16;
Δ = b2-4ac
Δ = 32-4·6·(-16)
Δ = 393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{393}}{2*6}=\frac{-3-\sqrt{393}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{393}}{2*6}=\frac{-3+\sqrt{393}}{12} $

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